C++ Program to Check Whether Number is Even or Odd

C++ Program to Check Whether Number is Even or Odd Using if-else

Determining whether a number is even or odd is fundamental in programming. This section will guide you through a C++ program that accomplishes this task using the if-else statement. We'll keep it simple and easy to understand, avoiding technical jargon.

Code

Explanation

• We start by including the necessary header files and defining the standard namespace.
• We declare an integer variable num to store the user's input.
• The user is prompted to enter a number using cout and cin for input.
• We use the modulus operator % to determine if the number is even or odd. If num % 2 equals 0, the number is even; otherwise, it's odd.

The program displays an appropriate message depending on the result of the if-else condition.

This C++ program provides a straightforward way to check whether a given number is even or odd. Using the if-else statement and the modulus operator, you can quickly analyze numeric values in your C++ programs, making it a valuable tool in your programming arsenal.

C++ Program to Check Whether Number is Even or Odd Using Ternary Operator

In C++ programming, determining whether a given number is even or odd is a fundamental task. It's an essential concept for decision-making within your programs. One efficient way to achieve this is using the ternary operator, a concise construct that simplifies conditional expressions.

Here's a straightforward C++ program that demonstrates how to employ the ternary operator to discern the parity of a number:

Explanation

This program begins by prompting the user to input a number. It then employs the modulo operator (%), which calculates the remainder when num is divided by 2. The number is even if the remainder is zero; otherwise, it's odd. The ternary operator (? ) prints the appropriate message conditionally.

This concise approach not only simplifies the code but also enhances its readability. It's a prime example of how C++ empowers programmers to perform complex tasks with concise and elegant solutions. So, try it, and you'll be effortlessly determining the parity of numbers in your C++ programs.

C++ Program to Check Whether Number is Even or Odd Using Bitwise Operators

In the world of programming, efficiency and performance are paramount. To determine whether a given number is even or odd, we can employ bitwise operators in C++. Bitwise operators manipulate individual bits of data and provide a swift and resource-efficient way to solve this common problem.

Code

Explanation

We start by including the necessary header files and defining our main function. Then we declare an integer variable num to hold the user's input. The user is prompted to enter a number; the input is stored in the num variable. The heart of this program lies in the if statement. We use the bitwise AND operator (&) to check the least significant bit of the num. If it's 1, the number is odd; otherwise, it's even. Finally, we display the result in a human-readable format.

This C++ program demonstrates how to leverage bitwise operators to determine whether a number is even or odd efficiently. We can inspect the least significant bit by using bitwise AND (&), making it a simple and elegant solution for this fundamental programming task.