FizzBuzz Program in Python

Introduction to Fizzbuzz Program in Python

In the Fizz, Buzz, and Fizz Buzz groups, the programming assignment Fizz-Buzz demonstrates the division of numbers. Assume the user is given the number 'n,' and they are asked to display the string representations of all the numbers from 1 to n. However, there are some restrictions, such as:

• If the number can be divided by 3, it will output Fizz instead of the number.
• If the number is divisible by 5, the result will display Buzz instead of the number.
• And if the given number is divisible by both 3 and 5, Fizz Buzz will be printed instead of the number.
• If the number cannot be divided by 3 or 5, it will be printed as a string.

Example to Show Python Program for the Fizz Buzz

Input: Take the numbers as input from the user, separated by commas (",").

1,2,3...100

Output:

1, 2, Fizz, 4, Buzz, Fizz, 7, 8, Fizz, Buzz, 11, Fizz, 13, 14, FizzBuzz…

So as you can see in the above output that where there is a number which is multiple of 3 the program prints "Fizz", prints "Buzz" at the place of a number which is a multiple of 5 and prints "FizzBuzz" at the place of number which is multiple of 3 and 5 both.

Explanation:

• 1 and 2 are not the multiples of 3 or 5, so they both will be printed as it is.
• 3 is a multiple of 3, so Fizz will be printed.
• 4 is not a multiple of 3 or 5, so it will be printed as it is.
• 5 is a multiple of 5, so Buzz will be printed in place of 5.
• 6 is a multiple of 3, so Fizz will be printed.
• 7 and 8 are not the multiples of 3 or 5, so they both will be printed as it is.
• 9 is a multiple of 3, so Fizz will be printed.
• Because 10 is a multiple of five, we print Fizz.
• 11 is not the multiple of 3 or 5, so it will be printed as it is.
• 12 is a multiple of 3, so Fizz will be printed.
• 13 and 14 are not the multiples of 3 or 5, so they both will be printed as it is.
• Because 15 is a multiple of 3 and 5, FizzBuzz will be printed in place of 15. and so on...

Implementation in Python

We'll use a for-in-range loop to solve the fizzbuzz problem in python. We use a for-in-range loop to traverse numbers from 1 to 100 in the code snippet below.

Output :

Check if the number is divisible by 3 or 5 or both using if-elif-else.

• As shown in the code above, check both numbers and then check each number individually.
• Print the number itself if the number is not divisible by 3 or 5.

See Also:

• Factorial Program in Python
• Factorial Using Recursion in Python